Plotting a position function - Help!

1 次查看（过去 30 天）
Seb.W
Seb.W 2013-3-25
I am asked to plot the position function
r(t) = -ti + (t^3)/3)j
over the interval t = -2 < t < 2
where i and j are unit vectors. I've drawn it out by hand but I can't get the same result through Matlab. My problem is that I'm not really sure about how to get those i and j vectors into the expression.
I tried something like
ri = [1;0;0]
rj = [0;1;0]
t = -2:0.1:2
r = -t.*ri + ((1/3)*t.^3).*rj
but got a message saying "Error using . * Matrix dimensions must agree."
Can someone give me some pointers on how to do this.
Many thanks.

请先登录，再回答此问题。

回答（1 个）

Walter Roberson
Walter Roberson 2013-3-25
编辑：Walter Roberson 2013-3-25
hint:
fx = @(x) sin(x.^2) + cos(x) * 1j;
y = fx(0:.1:1);

类别

在 Help Center 和 File Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by