Plotting a position function - Help!
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I am asked to plot the position function
r(t) = -ti + (t^3)/3)j
over the interval t = -2 < t < 2
where i and j are unit vectors. I've drawn it out by hand but I can't get the same result through Matlab. My problem is that I'm not really sure about how to get those i and j vectors into the expression.
I tried something like
ri = [1;0;0]
rj = [0;1;0]
t = -2:0.1:2
r = -t.*ri + ((1/3)*t.^3).*rj
but got a message saying "Error using . * Matrix dimensions must agree."
Can someone give me some pointers on how to do this.
Many thanks.
回答（1 个）
Walter Roberson
2013-3-25
编辑：Walter Roberson
2013-3-25
hint:
fx = @(x) sin(x.^2) + cos(x) * 1j;
y = fx(0:.1:1);
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