Hints:
data=[0.52299 0.000237
1.04598 0.041598
1.56897 0.005755
2.09196 0.012987
2.614949 0.009894
3.137939 0.050168
3.660929 0.00584
4.183919 0.045582
4.706909 0.00007
5.229899 0.054282
5.752889 0.002132
6.275879 2.508755
6.798868 3.193212
7.321858 3.460158
7.844848 3.206859
8.367838 2.923524
8.890828 2.23533
9.413818 1.127799
9.936808 0.429399
10.459798 0.814943];
Next: Distance for x-axis, velocity for y-axis
x_distance=data(:,1);
y_velocity=data(:,2);
Next: "Find and load the closest to 1m on the x-axis, and also the corresponding the velocity in y-axis."
What does the 1m menas?
Is that closset between x_distance & y_velocity?? If so, then
close_1m=x_distance-y_velocity;
Then finding the correcponding index
idx=find(close_1m==min(close_1m))
Please do the rest part by yourself.
:)
