matrix manupulation and reading diagonally

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NIKHIL
NIKHIL 2020-12-8
评论： NIKHIL 2020-12-11
Hello Team,
i have a matrix
Matrix_test = [13,10,5,2;7,14,11,6;3,8,15,12;1,4,9,16];
I want to read the matrix in the order mentioned in the matrix.
Starting from left bottom (1), then right top (2) and then again 2nd diagonal from left (3,4) and then 2nd right diagonal (5,6) and so on and so forth.
Please support in resolving it.
Edit : i there any way to create this kind of matrix for any n-by-n matrix automatically. i have created this Matrix_test manually but if i want 8x8 matrix in similar pattern . How to create it through generic code.
Thanks in advance.

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采纳的回答

Stephan
Stephan 2020-12-8
This function may help:
M = [13,10,5,2;7,14,11,6;3,8,15,12;1,4,9,16]
MyResult = readDiag(M)
function R = readDiag(M)
R = cell(2,numel(diag(M)));
for k = 1:numel(diag(M))-1
R{1,k} = diag(M,-numel(diag(M))+k);
R{2,k} = diag(M,numel(diag(M))-k);
end
R = reshape(R,[],1);
R = [R; {diag(M)}];
R = cell2mat(R);
end
result is:
M =
13 10 5 2
7 14 11 6
3 8 15 12
1 4 9 16
MyResult =
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
  2 个评论
NIKHIL
NIKHIL 2020-12-11
Hello Stephen, I have edited one additional question related to this query. How to create similar type of Matrix_test automatically with some code. can you please revert back to this query also ?

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更多回答（1 个）

Bruno Luong
Bruno Luong 2020-12-8
编辑：Bruno Luong 2020-12-8
Matrix_test = [13,10,5,2;7,14,11,6;3,8,15,12;1,4,9,16]
[m,n]=size(Matrix_test);
[i,j]=ndgrid(1:m,1:n);
jmi = j(:)-i(:);
[~,is]=sortrows([-abs(jmi) jmi]);
Matrix_test(is)
  4 个评论
显示 2更早的评论
Bruno Luong
Bruno Luong 2020-12-11
Create matrix with dimension m x n.
m=8; n=8;
[i,j]=ndgrid(1:m,1:n);
jmi = j(:)-i(:);
[~,is]=sortrows([-abs(jmi) jmi]);
M=zeros(m,n);
M(is)=1:m*n
NIKHIL
NIKHIL 2020-12-11
Thank you so much Bruno for quick response.
It is working really good

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