Determine the extreme values for the function f(x)

Question

Duncan Weakley 2020-12-8

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https://ww2.mathworks.cn/matlabcentral/answers/687343-determine-the-extreme-values-for-the-function-f-x

回答： Rohit Pappu 2020-12-28

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Hi there

I need to determine the extreme values for the function f(x) on the interval [0,4]

I am gridlocked with this

I am trying to use vpa, but only get one answer

I need to determine the local maximum and mininum values as well as global

I need this rounded to 4 decimals, and I dont see how simply reading it of the graph can help since 1. the graph give 3 decimals and 2. I dont see that i can place the cursor accurate enough

syms x
total_function = x.*(cos(x.^2)) - exp(sqrt(x))+x.^3 - 4*(x.^2);
f = x.*(cos(x.^2)) - exp(sqrt(x));
g = x.^3 - 4*(x.^2);
dif = diff(x.*(cos(x.^2)) - exp(sqrt(x))) + diff(x.^3 - 4*(x.^2));
vpasolve(dif == 0, x, 4);
extrema = vpa(ans, 6)
fplot(total_function)
xlim([0 4])

Thank you for your help in advance

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Answer 1

Rohit Pappu 2020-12-28

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https://ww2.mathworks.cn/matlabcentral/answers/687343-determine-the-extreme-values-for-the-function-f-x#answer_585617

在 MATLAB Online 中打开

To determine the extrema, optimization toolbox can be used . For example

%% Finding local minima in [0,4] using fminbnd
minima = fminbnd(@(y) y.*cos(y.^2) - exp(sqrt(y))+y.^3-4.*(y.^2),0,4);
%% Finding local minima of -f(x) to get the maxima of f(x)
maxima = fminbnd(@(y) -y.*cos(y.^2) + exp(sqrt(y))-y.^3+4.*(y.^2),0,4);

To determine the global extrema, GlobalSearch can be used