Improving a search algorithm

2 次查看(过去 30 天)
Natialol
Natialol 2013-3-26
Hello,
I would like suggestions on how to make the search below more efficient. I concatenate in another script to obtain numeric strings eg 0120001410. I then use the search function below to search for 0110001110 in row 1 obtain the corresponding value in row 2. Can I use logical indexing for this, if so, how.
function y= binge(x)
binge= [00000001, 00000010, 00000020, 00000021, .........,90000000;
0.11111, 2.4433, ..................................,7.2];
i=1;
length=size(binge,2);
while i<=length
if abs(x-binge(1,i))<10e-5
y=binge(2,i);
break;
end
i=i+1;
end
if (i>length)
error('wrong');
end
end
Thanks MN

采纳的回答

PT
PT 2013-3-26
function y = binge(x)
binge= [00000001, 00000010, 00000020, 00000021, .........,90000000;
0.11111, 2.4433, ..................................,7.2];
y = binge(2,binge(1,:) == x);
%or to use the same tolerance as you specified,
% y = binge(2,abs(x - binge(1,:)) < 1e-5);
  2 个评论
Natialol
Natialol 2013-3-29
Thanks PT, can I further improve the search?? The fitness function of which this search is a sub component still takes a very very long time.
Thanks
PT
PT 2013-4-1
If your table is sorted, you can use a more advanced algorithm. Have you Profiled the run?

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Matrix Indexing 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by