parfor: slicing variable

Question

Dan H 2020-12-9

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/688699-parfor-slicing-variable

回答： Walter Roberson 2020-12-9

采纳的回答： Walter Roberson

在 MATLAB Online 中打开

Hello,

I ask for assistance with slicing a variable for use with "parfor".

The challenge is, I don't want to / don't need to iterate over the whole array, but I need to change the values of some segments of the array.

The segment size to be changed is determined before the loop (variable "indices" and "step").

So the loop variable ("ii") is not identical to the array index.

Best regards,

Dan

clear all;
a = rand(20,1); % vector to be modified 
b = a;
indices = [2, 5, 9, 14]; %arbitrary start indices, for which the following n values should be changed
step = [1, 2, 2, 4]; % number of values to be changed
%% the for loop works
for ii = 1 : length(indices)
    start_index = indices(ii);
    end_index = start_index + step(ii);
    a(indices(ii) : indices(ii)+step(ii)-1) = nan(step(ii), 1);
end
%% parfor does not work
parfor ii = 1 : length(indices)
    start_index = indices(ii);
    end_index = start_index + step(ii);
    b(start_index : end_index) = nan(step(ii), 1);
end

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Walter Roberson 2020-12-9

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/688699-parfor-slicing-variable#answer_570504

在 MATLAB Online 中打开

This is not something you can do with parfor. parfor can only be used where the indices written to are a very simple computation from the indices.

I suggest you consider using sub2ind() to build up lists of linear indices to change, and then do a simple non-parallel b(list_of_indices) = nan .

If necessary (very long list) you could compute the indices in a parfor, returning them as data inside cell locations, like

parfor ii = 1 : length(indices)
    start_index = indices(ii);
    end_index = start_index + step(ii);
    bidx{ii} = start_index : end_index - 1;
end
b(horzcat(bidx{:})) = nan;