Solution of ODE in different time intervals

2 次查看(过去 30 天)
I want to solve ODE as a function over three different intervals [0,1],[1,1.2] and [1.2,3].
My function to solve my ODE is "solveODE" as following:
function [x, tinter, xinter] = solveODE(xdot, T, t0, ...
x0, u)
[tinter,xinter] = ode45(xdot, ...
[t0, t0+T], x0,u);
x = xinter(size(xinter,1),:);
end
where: "xdot" is my ODE function here k1 is constant has different valuesaccording to each of three intervals.
ODE function to be solved is as following:
function xprime = xdot(t, x, u, T)
xprime =[x(2);...
-k1*x(2)+k4*u(1)];
end
  2 个评论
Jan
Jan 2013-3-28
编辑:Jan 2013-3-28
What is your question? Which problems do you observe? How do you call solveODE?
maro
maro 2013-3-29
y file is complicated but I will make it simpler. if I have this simple ODE function:
function xdot=m(x,t)
xdot=k1*x(1);
end
Where k1 is a constant changing according to the time intervals (say for [0,1] k1=1, for [1,3] k1=2, for [3,10] k1=3).
I want to solve that ODE with ode45 command as a function over the different three intervals for example:
function [x, tinter, xinter]=solveODE(xdot,T,t0,x0)
[tinter,xinter] = ode45(system,[t0, t0+T], x0, options, u);
x = xinter(size(xinter,1),:);
end
where t0 change every iteration.

请先登录,再进行评论。

回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Ordinary Differential Equations 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by