colon operation (:) causes parfor to fail on cell array
1 次查看(过去 30 天)
显示 更早的评论
The following code causes Matlab to throw subscript assignment error:
s=cell(1,20);
parfor i = 1:20
s{:,i}=1;
end
However, when the colon operator is replaced with a 1, there is no error:
s=cell(1,20);
parfor i = 1:20
s{1,i}=1;
end
My guess is this involves a slicing issue somehow. Any insights?
1 个评论
Sergio Santos
2015-2-16
There is a solution to this. Reshaping whatever you want to send to parfor and turning it into a single column or raw vector. Also make a vector to store the length of each vector you reshape. Then when the operation is finished reshape back into matrix form. Shaping and reshaping is very fast and can be fastly done by a single worker, i.e. no need parallel computing.
采纳的回答
更多回答(2 个)
Cedric
2013-3-28
编辑:Cedric
2013-3-28
It has a priori nothing to do with PARFOR; the expression involving the colon on the left hand side is a comma separated list (CSL), so you cannot have the scalar 1 on the right hand side. Try it with a simple FOR loop and there will be no difference.
I don't know exactly what you want to do with that, but I guess that it is something like
s(:,i) = {1} ;
7 个评论
Cedric
2013-3-29
Thank you for the update! I will think about it a bit more about it and perform a few tests on my side.
Ben
2013-4-12
please tell us they working on a patch. i've come across this bug too now in 2013a
0 个评论
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Parallel for-Loops (parfor) 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!