code is too long
显示 更早的评论
a = 4;
b = input ('2+2=? ')
if b == a
'ok'
else
b = input ('retry ')
if b == a
'ok'
else
b = input ('retry ')
if b == a
'ok'
else 'NOK'
end
end
end
采纳的回答
Image Analyst
2013-3-31
编辑：Image Analyst
2013-3-31
I think you want
a = 4;
b = 0;
while b ~= a
b = input ('2+2=? ');
if b == a
break;
end
fprintf('Incorrect. Try again.\n');
end
fprintf('Correct.\n');
1 个评论
Image Analyst
2013-3-31
If you want to limit it to three tries, add a counter:
a = 4;
b = 0;
counter = 1;
while b ~= a && counter <= 3
b = input ('2+2=? ');
if b == a
break;
end
fprintf('Incorrect. Try again.\n');
counter = counter + 1;
end
if counter <= 3
fprintf('Correct.\n');
end
更多回答（1 个）
Nicolò
2013-3-31
0 个投票
2 个评论
Image Analyst
2013-3-31
This is not an answer to your question. It should have been a comment to my answer so I'll put the response there.
Nicolò
2013-3-31
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