Delete rows from an array
显示 更早的评论
Good afternoon
I have a long array of numbers, CEC (52560x1) and I would like to delete the rows in the following way:
r = 1:1:8760
t = 0:1:8759
CEC((2+6*t):(6*r))
I tried to set it into a loop by:
for r = 1:1:8760
for t = 0:1:8759
CEC((2+6*t):(6*r)) = [];
end
end
But it is not working for me. Any ideas?
Thank you!
3 个评论
SHIVAM KUMAR
2020-12-15
Couldn't get how you want to delete in a 1 D array like that .
CEC((2+6*t):(6*r)) = [];
This shall change all locations from 2+6*t to 6* r to empty.
and doing in loop means entire array will become empty except index [1,2]
Ricardo López
2020-12-15
Image Analyst
2020-12-15
Please give some actual numbers. For example, what indexes represent the first set of rows to delete, and the second set of rows to delete?
采纳的回答
David Hill
2020-12-15
a=CEC(1:6:52560);
CEC=zeros(size(CEC));
CEC(1:6:52560)=a;
更多回答（1 个）
SHIVAM KUMAR
2020-12-15
编辑：SHIVAM KUMAR
2020-12-15
Your code will work like this if used on 1 D array .
CEC((2+6):end) = [0];
If you are using that your array shall be 52560X52560.
then you can use
for r = 1:1:8760
for t = 0:1:8759
CEC((2+6*t),(6*r)) = [0]; %Use a comma
end
end
1 个评论
SHIVAM KUMAR
2020-12-15
ie. only have values for index 1 to 8 and all other indexes will be 0.
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