compacting a large number of plot lines

Question

Opariuc Andrei 2020-12-16

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/695160-compacting-a-large-number-of-plot-lines

评论： Opariuc Andrei 2020-12-17

func0=@(x) 5/3*cosd(0)-5/2*cosd(x)+11/6-cosd(40-x);
[phi0 valf]=fzero(func0,0);
func20=@(x) 5/3*cosd(20)-5/2*cosd(x)+11/6-cosd(40-x);
[phi20 valf]=fzero(func20,20);
func40=@(x) 5/3*cosd(40)-5/2*cosd(x)+11/6-cosd(40-x);
[phi40 valf]=fzero(func40,40);
func60=@(x) 5/3*cosd(60)-5/2*cosd(x)+11/6-cosd(40-x);
[phi60 valf]=fzero(func60,60);
func80=@(x) 5/3*cosd(80)-5/2*cosd(x)+11/6-cosd(40-x);
[phi80 valf]=fzero(func80,80);
func100=@(x) 5/3*cosd(100)-5/2*cosd(x)+11/6-cosd(40-x);
[phi100 valf]=fzero(func40,100);
plot([0 20 40 60 80 100],[phi0 phi20 phi40 phi60 phi80 phi100]);grid on;

all functioning ,but how can i do this from 0 to 360 degrees without having to write a large number of lines ?

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Answer 1

Subhadeep Koley 2020-12-16

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/695160-compacting-a-large-number-of-plot-lines#answer_577315

在 MATLAB Online 中打开

ind = 1;
angleValues = 0:20:360; % Modify angle values as per your requirement
phiValues = zeros(1, numel(angleValues));
for idx = angleValues
func = @(x) 5/3*cosd(idx)-5/2*cosd(x)+11/6-cosd(40-x);
phiValues(ind) = fzero(func, idx);
ind = ind+1;
end
figure
plot(angleValues, phiValues)
grid on

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Opariuc Andrei 2020-12-16

yeah ,turns out i introduced some error in what i showed ,in func 100 and the second cosd() is not always cosd(40-x) it actually scales/grows from 0 ,like in the image below with a 10 by 10 degree step cosd(0-x)/ cosd(10-x) and so on.

and my plot looks like this

and what attempted with what you provided is

ind =1;

angleValues = 0:1:360;

phiValues = zeros(1, numel(angleValues));

for idx = angleValues

func = @(x) 5/3*cosd(idx)-5/2*cosd(x)+11/6-cosd(idx-x);

phiValues(ind) = fzero(func, ind);

ind = ind+1;

end

and i get an error that says

" Exiting fzero: aborting search for an interval containing a sign change

because NaN or Inf function value encountered during search.

(Function value at -Inf is NaN.)

Check function or try again with a different starting value.

Exiting fzero: aborting search for an interval containing a sign change

because NaN or Inf function value encountered during search.

(Function value at -Inf is NaN.)

Check function or try again with a different starting value."

ind =1;

angleValues = 0:1:360;

phiValues = zeros(1, numel(angleValues));

for idx = angleValues

if ind > 360

func = @(x) 5/3*cosd(idx)-5/2*cosd(x)+11/6-cosd(idx-x);

phiValues(ind) = fzero(func, ind);

ind = ind+1;

end

i tried adding an if in the for loop, i got rid of the inf error but my plot is a flat line .

Sorry for my mistake in the original post .

Subhadeep Koley 2020-12-17

在 MATLAB Online 中打开

@Opariuc Andrei You have to pass idx to fzero, not ind. The variable ind is to access phiValues.

Use this code snippet.

ind = 1;
angleValues = 0:10:360;
phiValues = zeros(1, numel(angleValues));
for idx = angleValues
    func = @(x) 5/3*cosd(idx)-5/2*cosd(x) + 11/6-cosd(idx-x);
    phiValues(ind) = fzero(func, idx);
    ind = ind+1;
end
figure
plot(angleValues, phiValues)
grid on
axis tight

Opariuc Andrei 2020-12-17

tried that too after i posted here second time ,it's just that the graph seemed a little fishy to me when i tried a 1 degree step .

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compacting a large number of plot lines

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