Reading many files in one loop

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John
John 2013-4-4
How can I read file names and convert them to a matrix? I have more than one file and I want to read their contents in one loop of the program. Thanks
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Jan
Jan 2013-4-4
It is not useful to convert filenames to a matrix. Do you want to import the file's contents into a matrix?
John
John 2013-4-12
no I need to read the contents of a specific folder's file names (as text), then run selection rule to pick names only that i want.
The problem is that files being send to a folder, with names of the format (yyyymmddhh.jpg) so each day there is a marked file as (yymmddT.jpg)... (T for terminate). The names are varying, i can't read all by fopen commands, i can't specify the required name unless they are in some form.

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采纳的回答

Ahmed A. Selman
Ahmed A. Selman 2013-4-18
Download a function file called folderFiles.m.
http://www.mathworks.com/matlabcentral/fileexchange/40877-folderfiles-m
It'll do the job for you, hopefully.

更多回答（2 个）

ChristianW
ChristianW 2013-4-4
doc dir
D = dir([myfolder 'my*file*name*.*']);
files = {D.name}';
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John
John 2013-4-12
how to use files? I used it like
D = dir(['C:\Documents and Settings\John\My Documents\MATLAB\Pic_Down' '*.jpg'])
files = {D.name}';
files =
{}
any ideas?
Jan
Jan 2013-4-18
编辑：Jan 2013-4-18
This means, that no file matchs the filter:
'C:\Documents and Settings\John\My Documents\MATLAB\Pic_Down*.jpg'
Perhaps you want:
'C:\Documents and Settings\John\My Documents\MATLAB\Pic_Down\*.jpg'
Note: fullfile() is much better for constructing file names than STRCAT, HORZCAT or [.].

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Jan
Jan 2013-4-4
See: http://www.mathworks.com/matlabcentral/answers/57446-faq-how-can-i-process-a-sequence-of-files
It is always a good idea to read the FAQ, because it is efficient to profit from the errors of others.

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