Accessing values of fieldnames in a structure without using the fieldnames function

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Hi all,
I've got a structure which has 20 different field names, e.g. 'fieldname01','fieldname02' etc.
Each fieldname has a numeric value, such as:
fieldname01: 0.56 fieldname02: 0.93 fieldname03: -0.34
Up to fieldname20
I need to access the numeric values of certain field names, for example the 2nd, 5th and 15th. Just wondering what would be the right way about doing this without using the fieldnames function if that's possible at all?
Thank you.

采纳的回答

Sven
Sven 2013-4-4
编辑:Sven 2013-4-4
Hi Jess,
Use parentheses:
S = struct('field1',1,'field2',2)
fieldStr = ['fields' num2str(1)]
S.(fieldStr)
ans =
1
Or, with your particular example:
for i = 1:20
val = S.(sprintf('fieldname%02d',i))
end
Please note however that the "right" way to store data from 1 to 20 isn't in a structure with the number built into the name. Instead it sounds like you should be using an array (or cell array if your datatypes are different).
For example:
myData = [12 10 3];
is much cleaner than:
myData.element1 = 12
myData.element2 = 10
myData.element3 = 3

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