problem using num2str and bin2dec in size

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ghattas akkad
ghattas akkad 2013-4-4
having an array of 32*32 when using num2str i get a char array of 32*94 why? i cannot use bin2dec on it
data = uint32(randi(2^31,[32,1]));
m = de2bi((data),32);
groups = num2str(m');
the array groups will be of type char 32*94 i cannot convert it to decimal :S
- - - Updated - - -
tic
data = uint32(randi(2^31,[32,1]));
m = de2bi((data),32);
groups = (m');
power2=[1,32];
for i=1:32
power2(i)=2^(i-1);
end
power2=uint32(power2);
decnum=[1,32];
for i=1:32
decnum(i)=(sum(power2.*groups(i,:)));
end
decnum=uint32(decnum);
toc
this is the updated code but it is somekind of slow if i want to do it on 500 000number any suggestions plz?

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采纳的回答

Iman Ansari
Iman Ansari 2013-4-5
Hi
groups(:,1:3:end) %makeing result 32*32 again
Try this(Your updated code):
data = uint32(randi(2^31,[32,1]));
m = de2bi((data),32);
groups = num2str(m');
a=groups(:,end:-3:1);
b=bin2dec(a);
c=uint32(b);

更多回答（3 个）

ghattas akkad
ghattas akkad 2013-4-5
thank you how did this do it ?
  1 个评论
Iman Ansari
Iman Ansari 2013-4-5
See this:
m = de2bi((4),8)
groups = num2str(m)
groups2 = groups(1,1:3:end)
the groups has two space between its numbers.

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ghattas akkad
ghattas akkad 2013-4-5
there is some problem the result of c in your code after the bin2dec is different then the ones i obtained in the array decnum
  5 个评论
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Iman Ansari
Iman Ansari 2013-4-5
No:
clear
%%%%%mine
data = uint32(randi(2^31,[32,1]));
m = de2bi((data),32);
groups1 = num2str(m');
a=groups1(:,end:-3:1);
b=bin2dec(a);
c=uint32(b);
%%%%%%yours
groups = (m');
power2=[1,32];
for i=1:32
power2(i)=2^(i-1);
end
power2=uint32(power2);
decnum=[1,32];
for i=1:32
decnum(i)=(sum(power2.*groups(i,:)));
end
decnum=uint32(decnum);
mineVsyours=[c decnum']
ghattas akkad
ghattas akkad 2013-4-5
i think my code has a problem :) thank you :D

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ghattas akkad
ghattas akkad 2013-4-5
when update the code to look like this clear all close all
tic
data = uint32(randi(2^31,[500000,1]));
m = de2bi((data),32); groups = num2str(m'); a=groups(:,end:-3:1);
b=bin2dec(a); c=uint32(b);
toc
generate 500 000 numbers i get this error
Error using bin2dec (line 36) Binary string must be 52 bits or less.
Error in datatobin2 (line 12) b=bin2dec(a);
why ??
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ghattas akkad
ghattas akkad 2013-4-5
generate 500 000 numbers convert them to binary to group each set of bits together like a group of 1st bits = 1st row group of second bits=second row..... then convert them to decimal and send them to fpga using DMA to my sequential sorter
Iman Ansari
Iman Ansari 2013-4-5
500000 is very big but for lower number like 1000:
clear
data = uint32(randi(2^31,[1000,1]));
m = de2bi((data),32);
groups1 = num2str(m');
a=groups1(:,end:-3:1);
b=0;
for i=1:52:size(a,2)
b=b+bin2dec(a(:,i:min(i+51,end))).*2^(i-1);
end
But I think you shouldn't use c=uint32(b) after this.

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