how to divide the range of given integer number

Question

Jimmy cho 2020-12-21

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/699240-how-to-divide-the-range-of-given-integer-number

评论： Image Analyst 2020-12-21

Hi guys,

Might the deadline of my problem isn't understandable, so here Im explaining my problem.

Im trying to do a range of given integer number between negative and positive (including zero and assume zero is positive ..this just assumption in my case) equally -meaning by equally that the negative number and positive numbers are equally in the two sides, this means :

GivenNumber is an integer parameter (assume it's bigger than 0 )

lets assume I have number 20, GivenNumber=20 so the output is the range : [-10:9] , implicitly the number of numbers/samples in the range [-10:9] are 20 which it's the Givennumber - you can easily see the negative numbers are equally to the positive numbers (including zero as my assumption as positive).

lets assume I have number 10, GivenNumber=10 so output is the range : [-5:4] , implicitly the number of numbers/samples in the range [-5:4] are 10 which it's the Givennumber - you can easily see the negative numbers are equally to the positive numbers (including zero as my assumption as positive).

lets assume I have number 30, GivenNumber=30 so output is the range : [-15:14] , implicitly the number of numbers/samples in the range [-15:14] are 30 which it's the Givennumber - you can easily see the negative numbers are equally to the positive numbers (including zero as my assumption as positive).

So how can I do a function in matlab to get as parameter : GivenNumber , the output is the range as explained above?

Appreciated !

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Answer 1

Walter Roberson 2020-12-21

1
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https://ww2.mathworks.cn/matlabcentral/answers/699240-how-to-divide-the-range-of-given-integer-number#answer_581020

在 MATLAB Online 中打开

for GivenNumber = [20 10 30 3 25]
  Walters_Half = GivenNumber/2;
  ceil(-Walters_Half) : ceil(Walters_Half)-1
end
ans = 1×20
   -10    -9    -8    -7    -6    -5    -4    -3    -2    -1     0     1     2     3     4     5     6     7     8     9
●
ans = 1×10
    -5    -4    -3    -2    -1     0     1     2     3     4
●
ans = 1×30
   -15   -14   -13   -12   -11   -10    -9    -8    -7    -6    -5    -4    -3    -2    -1     0     1     2     3     4     5     6     7     8     9    10    11    12    13    14
●
ans = 1×3
    -1     0     1
●
ans = 1×25
   -12   -11   -10    -9    -8    -7    -6    -5    -4    -3    -2    -1     0     1     2     3     4     5     6     7     8     9    10    11    12
●