- The height is the first component of the state vector. I'll just call the state vector X is in the code below. So you can just back out h = X(1).
- Acceleration...you have the expression in the dX vector, the second component. To compute the acceleration as a function of time simply compute this expression in your main function, the function that is calling Beschleunigung().
- The best and most elegant way to do this is to use events functions. Run in the command window the built-in demo ballode and check out the code.
Simulating a free-fall project with ode45
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Hallo everybody, now that I've the basic solution for my ode45-method, I've another three questions.
- How do I add differntials of higher or lower orders in one of the other differntial-equation, like in my code. 'rho' is depended on the height h, but that is the first order of the ode, so how do I implement, the first order in the second order?
function dv = Beschleunigung(~, hv)
g = 9.81;
R = 8.31446261;
M = 0.0289586;
m = 120;
c_w = 0.28;
A = 2.7;
p_0 = 101325;
T_EO = 293.15;
rho_0 = (p_0 * M) / (R * T_EO);
v = hv(2); % velocity, positive downwards
dv = [
-v; % dh/dt
g-1/(2*m)*c_w*A*rho_0 * exp(-g*M*h(1)/R*T)*v^2]; % dv/dt
end
2. Since my project needs to show all forms of motion-equations (acceleration, speed, height), how do I plot the acceleration, with is the derivate of the ode45-method
3. And since it is required to name a timespan, and especelly the end, is there a possibility to let the method end, even when you do not exactly know the time needed, to reach a height of 0, in my specific case?
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Mischa Kim
2020-12-23
Hallo Lukas,
function dX = Beschleunigung(~, X) % X is the state vector X = [h; v]
g = 9.81;
R = 8.31446261;
M = 0.0289586;
m = 120;
c_w = 0.28;
A = 2.7;
p_0 = 101325;
T_EO = 293.15;
rho_0 = (p_0 * M) / (R * T_EO);
h = X(1); % position or height
v = X(2); % velocity, positive downwards
dX = [-v; % dh/dt
g-1/(2*m)*c_w*A*rho_0 * exp(-g*M*h/R*T)*v^2]; % dv/dt; T not yet defined?
end
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