Filling in multidimensional array efficiently

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Haneen
Haneen 2020-12-23
回答： James Tursa 2020-12-23
I need to fill in array of the size (900,1800,80,60) --> (tr,t,f,ch) through a for loop. In every iteration, I will get a bunch of data for a particular f and ch. This bunch, call it b, is the size of 50 by1800 and sometimes it is 49 by 1800.
Example:
array(?,:,f_1,ch_1) = b
I wish in each loop to fill in bunch b in my array. Is there an easy way to determine "?" in each loop? Alternatively, is there an easier way to fill in "array"?

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采纳的回答

Matt J
Matt J 2020-12-23
If you want b to be inserted in the topmost rows of each array(:,:,f, ch), then it would be,
array(1:size(b,1),:,f, ch) = b
  2 个评论
Haneen
Haneen 2020-12-23
This looks good, the problem is that in the next iteration, the new b will erase the old b. I would like the "b's" to be inserted on top of each other
Matt J
Matt J 2020-12-23
In the next iteration, you will have a new f and ch, so each assignment will be to a new block of the array.

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更多回答（2 个）

Hiro Yoshino
Hiro Yoshino 2020-12-23
repmat may solve your issue - check up the link:
repmat function
  1 个评论
Haneen
Haneen 2020-12-23
repmat is for copying an array and concatinating; but here I am filling new data in every iteration. I am not sure how would repmat be of an help. Would you please elaborate?

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James Tursa
James Tursa 2020-12-23
Something like this maybe?
k = 1;
% your loop
b = r x 1800 matrix
f = whatever
ch = whatever
r = size(b,1);
array(k:k+r-1,:,f,ch) = b;
k = k + r;
% end loop
But it is not clear how f and ch change within the loop, so this might not work as written.

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