Logical function not returning correct value for smaller numbers

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Ravi Rahul Kumar Shah
编辑： Mischa Kim 2020-12-23
I am writing a function which sould return back the index of the searched value. Because the numbers are smaller, the buildin find is not working.
Most of the times it works, but if the number is really small, it is not working. The condition Vektor(k) == x is false, although the numbers are exactly same.
function index_1 = find_Index(x,Vektor)
for k = 1:length(Vektor)
if Vektor(k) == x
index_1 = k;
return;
end
end
end

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采纳的回答

Mischa Kim
Mischa Kim 2020-12-23
编辑：Mischa Kim 2020-12-23
Hi Ravi, try something like
if abs(Vektor(k) - x) < tol
and use tol to fine-tune your algorithm depending on how "different" your numbers are, e.g.
tol = 1e-4

更多回答（1 个）

Walter Roberson
Walter Roberson 2020-12-23
function index_1 = find_Index(x, Vektor)
index_1 = [];
[found, idx] = ismembertol(x, Vektor);
if found; index_1 = idx; end
This returns empty if no match, and the index of an "almost-exact" match if found . For example if x was sqrt(13)/3*3 and Vektor contained sqrt(13) then there is not a bit-for-bit equality, but ismembertol() would be willing to overlook the 4.44089209850063e-16 difference in values.
Or perhaps you would prefer
function index_1 = find_Index(x, Vektor)
[~, index_1] = min( abs(Vektor - x) );
which returns the index of the nearest value, even if numerically it is a distance. For example, the input could be 73 and the match might be against 100

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