Inverse matrix with for loop

Question

0 个投票

Using for loops, program a general code for calculating the inverse of a given matrix in the 2X2 and 3X3 cases.

Can someone help me? I'm learning to use the for loop and I don't know how to do that.

7 个评论
显示 5更早的评论隐藏 5更早的评论

Elizabeth Brito 2020-12-24

thanks i will go check it

Elizabeth Brito 2020-12-24

在 MATLAB Online 中打开

hi i checked that code but that is gauss method and i need cofactors method.

I made a new code but it doesn't work. Can you help me?

or how can i do it

C=[-2,3;
    6,5]
    
[m,n]=size(C)
z=zeros(m,n)
%cofactor
c1= C(2,2)
c2 = -C(1,2)
c3 = -C(2,1)
c4 = C(1,1)
%matriz del cofactor
c = [c1,c3;
     c2,c4]  
     
for i=1:m %filas 
  for j=1:n %columnas
    for k=transpose(c)
      z(i,j)= (1/det(C(i,j)))*k
    end
  end
end 

请先登录，再进行评论。

请先登录，再回答此问题。

Follow Question

Answer 1

Doddy Kastanya 2021-1-6

0 个投票

The way you prepare the cofactor is okay. You want to define your "k=transpose(c)" outside of the loop. The other thing that you need to remember is the intrinsic function "det" is to determine the determinant of a matrix. Applying it on an element of a matrix will just give you the element back. So, your code should look something like:

c=[c1, c3;c2, c4];

k=transpose(c); % or you could simply use k=c';

denum=det(C);

for i=1:m

for j=1:n

z(i,j)=1/denum*k(i,j);

end

The same principal is applicable for a 3x3 matrix. You just need to be careful in defining the cofactors (including the "+" and "-" signs). Good luck.

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

Inverse matrix with for loop

7 个评论
显示 5更早的评论隐藏 5更早的评论

回答（1 个）

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

类别

标签

Community Treasure Hunt

Inverse matrix with for loop

7 个评论 显示 5更早的评论 隐藏 5更早的评论

回答（1 个）

0 个评论 显示 -2更早的评论 隐藏 -2更早的评论

类别

标签

另请参阅

Community Treasure Hunt

7 个评论
显示 5更早的评论隐藏 5更早的评论

0 个评论
显示 -2更早的评论隐藏 -2更早的评论