清空筛选条件
清空筛选条件

Inverse matrix with for loop, dimensions are wrong I don't know how to fix it

1 次查看（过去 30 天）
Elizabeth Brito
Elizabeth Brito 2020-12-24
评论： Jan 2020-12-24
C=[-2,3;
6,5]
[m,n]=size(C)
z=zeros(m,n)
%cofactor
c1= C(2,2)
c2 = -C(1,2)
c3 = -C(2,1)
c4 = C(1,1)
%cofactor matrix
c = [c1,c3;
c2,c4]
for i= 1:m
for j= 1:n
for k=1/det(C(i,j))
for h= transpose(c)
z(i,j)= k*h
end
end
end
end
  1 个评论
Jan
Jan 2020-12-24
Before the readers can fix your code, they need to know, what you try to do. "Inverse matrix with foor loop" is not clear enough.
det(x) is x, if x is a scalar. So "for k=1/det(C(i,j))" is the same as "k = 1 / C(i,j)".
What is the purpose of "for h= transpose(c)"?

请先登录，再进行评论。

请先登录，再回答此问题。

回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Polynomials 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by