Problem with plotting equation

10 次查看(过去 30 天)
I have an implicit equation where x and y - variables. I want to make a graph, but ezplot function doesn't work. MATLAB writes: log(y/x)-STOI+(x/I_sat)*(y/x-1) cannot be plotted in the xy-plane. Also he offers to use fplot instead of ezplot, but it doesn't work correctly with fplot because, as far as I know, fplot doesn't work with implicit equations. So how can I solve this problem?
Also x should changes from 0 to 25. But I think it isn't a tough problem to solve.
  6 个评论
Star Strider
Star Strider 2020-12-25
The error is:
Error using ezplot (line 176)
log(y/x)-STOI+(x/I_sat)*(y/x-1) cannot be plotted in the xy-plane.
however using ezsurf also errors:
Error using ezgraph3>ezfixfun (line 682)
The expression log(y/x)-STOI+(x/I_sat)*(y/x-1) must only have 2 symbolic variables
Nopte that ‘STOI’ is a (1x251) double vector, and ‘I_sat’ is a scalar.
What do you want to do?
George Bashkatov
George Bashkatov 2020-12-25
I only want to plot the last equation. Other variables are only auxiliary.
"y" here is like a y=f(x). This is an inplicit equation, so I can't make equation like y=f(x) and I have to make and equation like f(x,y)=0.
I think x should cover the same range as I_0, but when I tryed to change x to I_0 it didn't work. The range of I_0 is 0..25.
Now I recognized that x and I_0 are the same variables. I substituted STOI with expression for this variable. After that in this formula I substituted b with expression for variable "b". And in expression for b I substituted the I_0 with x. So I had an expression with only two variables x and y without any vectors. But it also gives the same error.
syms x y;
ezplot('log(y/x)-(sigma_e/sigma_a)*(log(1+x*sigma_a*tau*lambda_0/(h*c))-log(1+(x*sigma_a*tau*lambda_0/(h*c))*exp(-alpha*L)))+(x/I_sat)*(y/x-1)');

请先登录,再进行评论。

采纳的回答

Mischa Kim
Mischa Kim 2020-12-26
Hi George, use fimplicit():
syms x y
f(x,y) = log(y/x)-(sigma_e/sigma_a)*(log(1+x*sigma_a*tau*lambda_0/(h*c))-log(1+(x*sigma_a*tau*lambda_0/(h*c))*exp(-alpha*L)))+(x/I_sat)*(y/x-1);
fimplicit(f)
Of course, you would have to assign values to the parameters.

更多回答(0 个)

产品


版本

R2020a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by