How can i convert this linear equation into a form which i can use linsolve() function?
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I wrote a code like;
function [a,b]=lin_reg(x,y)
a=0;
b=0;
for i = 1:length(x)
for j = 1:length(y)
a=(y(j)-b)/x(i);
b=y(j)-a*x(i);
end
end
end
But these code didn't help me to pass my tests, so i need an equation which i can use linsolve() function.
Thanks in advance.
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回答(1 个)
Pratyush Roy
2020-12-29
Hi,
Assuming that both x and y are arrays of shape 1*n, the following code snippet might be helpful
x_new = [x' ones(n,1)];
coeff = linsolve(x_new,y');
Here coeff is a 1*2 array where
a = coeff(1);
b = coeff(2);
Hope this helps!
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