Error using .* Matrix dimensions must agree.

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muhammad nur adri nawi
编辑： Image Analyst 2020-12-27
M = 25;
alpha = (M-1)/2;
n = 0:M-1;
hd = (2/pi)*((sin((pi/2)*(n-alpha)).^2)./(n-alpha));
hd(alpha+1)=0;
w_han = '(hann(M))';
h = hd .* w_han; %%%here is the error
  2 个评论
KALYAN ACHARJYA
KALYAN ACHARJYA 2020-12-27
编辑：KALYAN ACHARJYA 2020-12-27
Array multiplication between numeric array and character array??
> whos hd
Name Size Bytes Class Attributes
hd 1x25 200 double
>> whos w_han
Name Size Bytes Class Attributes
w_han 1x9 18 char
Aim?
w_han??
muhammad nur adri nawi
muhammad nur adri nawi 2020-12-27
编辑：Image Analyst 2020-12-27
%%% problem this code cannot run
M = 25;
alpha = (M-1)/2;
n = 0:M-1;
hd = (2/pi)*((sin((pi/2)*(n-alpha)).^2)./(n-alpha));
hd(alpha+1)=0;
w_han = '(hann(M))';
h = hd .* w_han.';
[Hr,w,c,L] = Hr_Type3(h);
subplot(2,2,1); stem(n,hd); title('Ideal Impulse Response')
axis([-1 M -1.2 1.2]); xlabel('n'); ylabel('hd(n)')
subplot(2,2,2);
stem(n,w_han);
title('Hann Window');
axis([-1 M 0 1.2]); xlabel ' n '); ylabel('w(n)')
subplot(2,2,3); stem(n,h);title('Actual Impulse Response')
axis([-1 M -1.2 1.2]); xlabel('n'); ylabel('h(n)')
w = w'; Hr = Hr';
w = [-fliplr(w), w(2:501)]; Hr = [-fliplr(Hr), Hr(2:501)];
subplot(2,2,4);plot(w/pi,Hr); title('Amplitude Response');grid;
xlabel('frequency in pi units'); ylabel('Hr'); axis([-1 1 -1.1 1.1]);

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采纳的回答

KALYAN ACHARJYA
KALYAN ACHARJYA 2020-12-27
编辑：KALYAN ACHARJYA 2020-12-27
In this case hd is numeric array with size 25
whos hd
Name Size Bytes Class Attributes
hd 1x25 200 double
Whereas w_han is character array with size 9
>> whos w_han
Name Size Bytes Class Attributes
w_han 1x9 18 char
Once you try to multiply between the numeric array and the character array, you supose to get an error as follows
Error using .*
Matrix dimensions must agree.
If somehow you increase the size of w_han to 25, then no error can occur. Are you really looking for that? In such case it get multiplied with ASCII code of respective character, see the example
>> a='m'
a =
'm'
>> b=5;
>> c=b.*a
c =
545
Here b is multiplied with ASCII code of m, which is 109, as
>> 5*109
ans =
545
I just want to mention this point, so that you can get the idea, if somehow an error cannot occur, it can happen in such a case.

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