Converting sequence to binary based on the value exceeding condition
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Say I have a sequence x = [2 4 3 7 5 4 3], and I want to convert the sequence to 1s and 0s based on if the value at each index position is greater than 5. So the output of the function would give y = [0 0 0 1 1 0 0]...what would this function look like?
I have attempted this from the below, could you also explain if this is the correct path?
Many thanks for your help
for i=length(x)
if x(i:end) > 5
y(i) = 1;
else
y(i) = 0;
end
回答（1 个）
Image Analyst
2020-12-27
One line of code is all it takes:
y = x > 5
1 个评论
Image Analyst
2020-12-27
or
y = x >= 5
depending on what you want. (Your question shows it both ways and is ambiguous.)
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2020-12-27
2020-12-27
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