Converting sequence to binary based on the value exceeding condition

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William Taylor
William Taylor 2020-12-27
评论： Image Analyst 2020-12-27
Say I have a sequence x = [2 4 3 7 5 4 3], and I want to convert the sequence to 1s and 0s based on if the value at each index position is greater than 5. So the output of the function would give y = [0 0 0 1 1 0 0]...what would this function look like?
I have attempted this from the below, could you also explain if this is the correct path?
Many thanks for your help
for i=length(x)
if x(i:end) > 5
y(i) = 1;
else
y(i) = 0;
end

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回答（1 个）

Image Analyst
Image Analyst 2020-12-27
One line of code is all it takes:
y = x > 5

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