Appropriate method for solving coupled pdes
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Hello. I am looking to solve the following system of modified wave equations: 
I have looked at pdepe and thought there might be an equivalent for hyperbolic equations. I thought of using the pde modeller in 2D with a thin domain and zero neumann boundary conditions on the sides but the equations did not fit the pde modeller (the single derivative time terms could not be accommodated in the standard form in pde modeller). Am I overlooking a method in matlab or simulink or do I have to write my own finite difference scheme? Many thanks for any pointers.
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Bill Greene
2020-12-31
编辑：Bill Greene
2020-12-31
Yes, although it is true that the documentation for pdepe describes it as a solver for parabolic systems, it can often obtain solutions to systems of hyperbolic PDE with no problems.
To convert your two-equation system to a form acceptable to pdepe, I defined two auxiliary variables to yield the following four-equation system
I made a few assumptions about the values of the constants, the initial, and boundary conditions and used the following MATLAB code to solve this system
function matlabAnswers_12_31_2020
nx=31;
x = linspace(0,1,nx);
nx2=ceil(nx/2);
t = linspace(0, 1, 50);
m = 0;
sol = pdepe(m,@pdefun,@pdeic,@pdebc,x,t);
u=sol(:,:,1);
v=sol(:,:,2);
figure; plot(x, u(end,:) ,x,v(end,:)); grid; legend('u', 'v');
title 'solution at final time';
figure; plot(t, u(:,nx2),t,v(:,nx2)); grid; legend('u', 'v');
title 'solution at the center as a function of time';
end
function [ c, f, s ] = pdefun ( x, t, U, dUdx)
a=1; b=1;
c=[1 1 1 1]';
f=[0 0 a^2*dUdx(1) a^2*b^2*dUdx(2)]';
s=[U(3) U(4) U(4) -U(3)]';
end
function u0 = pdeic(x)
u0=[sin(pi*x) sin(3*pi*x) 0 0]';
end
function [ pl, ql, pr, qr ] = pdebc ( xl, ul, xr, ur, t )
pl = ul;
ql = [0 0 0 0]';
pr = ur;
qr = [0 0 0 0]';
end
5 个评论
Issy
2020-12-31
Issy
2020-12-31
Bill Greene
2020-12-31
Oh yes, sorry, thanks for catching that! I corrected the code in my post above.
Issy
2020-12-31
Bill Greene
2021-1-1
Thanks for the check on the pdepe solution. When the boundary or initial conditions are discontinuous, solving hyperbolic PDE with pdepe can be challenging. I suspect this is why the documentation doesn't emphasize this class of problem.
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