Making an array using loop

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SWARNENDU PAL
SWARNENDU PAL 2020-12-30
A=[2;3;4;5;12;13;14;15;16;17;24;25;26;27;28;29;36;37;38;39;40;41;48;49;50;51;52;53;60;61;62;63;64;65;72;73;74;75;76;77;84;85;86;87;88;89;96;97;98;99;100;101;108;109;110;111;112;113;120;121];
How to make an array like A using loop. Thank you.
  3 个评论
SWARNENDU PAL
SWARNENDU PAL 2020-12-31
that is the array. There is a pattern,plz notice carefully. If you provide me any other option that will be also helpful.Thank you.
Rik
Rik 2020-12-31
编辑:Rik 2020-12-31
Help us help you: explain the pattern and we might be able to help you write the code to create it.
The pattern is not obvious to me (nor, apperently, to Cris). It is also missing from the OEIS, which is generally an indication that the sequence is fairly obscure.

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回答(1 个)

Paul Hoffrichter
Paul Hoffrichter 2020-12-31
编辑:Paul Hoffrichter 2021-1-1
Change ORIGINAL_POST to false to get slightly different result.
clearvars; clc; % remove previous debug runs
lenA = 60; % assumes you know the length of A
A = zeros(lenA,1); % pre-allocate A
maxSeqLen = 6;
ORIGINAL_POST = true;
if ORIGINAL_POST
start = 2;
seqLength = 4;
else
% rng(123);
start = randi(maxSeqLen,1);
seqLength = randi(maxSeqLen);
end
nominalSequence = 1:maxSeqLen;
skip = 7;
% Initialize
A(1:seqLength) = start:(start + seqLength - 1);
startLoc = seqLength + 1;
k = seqLength + 1;
while startLoc + maxSeqLen - 1 <= lenA
start = A(startLoc - 1) + skip;
A(startLoc:startLoc + maxSeqLen - 1) = start: start + maxSeqLen - 1;
start = start + maxSeqLen - 1 + skip;
startLoc = startLoc + maxSeqLen;
end
if startLoc <= lenA
maxSeqLen = lenA - startLoc + 1;
A(startLoc:startLoc + maxSeqLen - 1) = start: start + maxSeqLen - 1;
% if you cannot pre-allocate A, and have to enter values one at a time,
% then you can add elements like this: A = [A; new-value];
end
  2 个评论
Rik
Rik 2020-12-31
You don't print anything to the command window, so what is the clc doing? And why are you suggesting clear all? mlint is clearly warning you not to use this.
Paul Hoffrichter
Paul Hoffrichter 2021-1-1
编辑:Paul Hoffrichter 2021-1-1
clc - used to remove previous debug runs where printing was done.
clear all - good point. Edited to say clearvars.

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