Mirror pattern of the leading diagonal about the middle element of the matrix

1 次查看（过去 30 天）

显示更早的评论

Swati Sarangi 2021-1-2

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/706823-mirror-pattern-of-the-leading-diagonal-about-the-middle-element-of-the-matrix

评论： Star Strider 2021-1-5

采纳的回答： Star Strider

Hi All,

I am interested to create the following matrix but unable to think about the logic to create it.

for example : for n = 5 ; the elememts of leading diagonal are 2 1 0 1 2 and rest elements 0

for n = 7, the elements of the leading diagonal are 3 2 1 0 1 2 3 and rest elements are 0.

Any help will be highly appreciated.

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Star Strider 2021-1-2

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/706823-mirror-pattern-of-the-leading-diagonal-about-the-middle-element-of-the-matrix#answer_589078

在 MATLAB Online 中打开

This works for odd ‘n’:

dv = @(n) abs(diag(unique(fix(-n/2:n/2))));                     % Create Diagonal Matrix
n = 5;
m5 = dv(n)
n = 7;
m7 = dv(n)

producing:

m5 =
   0     0     0     0
   1     0     0     0
   0     0     0     0
   0     0     1     0
   0     0     0     2
m7 =
   0     0     0     0     0     0
   2     0     0     0     0     0
   0     1     0     0     0     0
   0     0     0     0     0     0
   0     0     0     1     0     0
   0     0     0     0     2     0
   0     0     0     0     0     3