correct quadrant and angle when not using roipoly

2 次查看（过去 30 天）
slowlearner
slowlearner 2021-1-2
编辑： slowlearner 2021-1-5
Hi I'm trying to make 2 objects in a picture the points of interest however, the problem I'm facing is that I can't get the angle of the point of interest. the simpler solution would be to do it with roipoly but then i wont understand the how...
The picture contains the 2 lego platforms I intend to mark as points of interests but when selecting the right one I get a square with the background table. So in the code I need to account for the angle, I'm trying to make all my codes more general purpouse hens the switch case i know i should implement it in a loop for more objects than two but that comes later at the moment i just need to solve this hurdle.
cam = webcam;
img_piece = snapshot(cam);
figure;imshow(img_piece);
hold on;
roi1 = drawpolygon;
mask1 = createMask(roi1);
draw(roi1);
mask2 = createMask(roi1);
mask = mask1 + mask2;
pause
maskedImg = img_piece;
for i = 1:size(img_piece,1)
for j = 1:size(img_piece,2)
if ~mask(i,j)
maskedImg(i,j,:) = [0 0 0];
end
end
end
figure;imshow(maskedImg);
%% EDIT: the code now contains the correct answer but for multiple uses you need to make it your own

请先登录，再回答此问题。

采纳的回答

Image Analyst
Image Analyst 2021-1-2
编辑：Image Analyst 2021-1-2
You need to use roipolyold() or drawpolygon() instead of all that with ginput(), etc.
  5 个评论
显示 3更早的评论
slowlearner
slowlearner 2021-1-5
I'm at a loss I just don't know how to "turn of" everything but the region drawn by the drawpolygon() function because i get a 4x2 array and don't know how to make that into the "area" if the angle is unknown. I guess i could work one out with cosinrule and sin but is this really the easiest way to code? Then I might just aswell keep the ginput() and start the maths....
slowlearner
slowlearner 2021-1-5
There is! just needed to add mask = createMask() updating the thread and thanking you for the guidance.

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 ROI-Based Processing 的更多信息

标签

产品


版本

R2020b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by