How to use unique in a conditional statement nested in for loop?
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I want to apply "unique" function on sol to get rid of repeated arrays.
n = 10000;
for a = 1:n
for b = 1:n
x = a^2-b;
y = sqrt(a^2+b^2);
if (mod(x,1)==0) && (mod(y,1)==0)
sol = [a,b]
end
end
end
So, for this code I tried
soln = unique(sol);
disp(soln)
But this approach displays only the last result due to loop. How can I fix it?
采纳的回答
Mischa Kim
2021-1-2
Usman, you could do it this way. First compute all solutions in a matrix X and then compute unique values.
n = 1000;
for a = 1:n
for b = 1:n
x = a^2-b;
y = sqrt(a^2+b^2);
X(b + (a-1)*b,:) = [x y];
end
end
Y = unique(X,'rows');
3 个评论
Usman Saleem
2021-1-2
Walter Roberson
2021-1-2
Apply it afterwards.
Note: since your loops are over integers, x = a^2-b; is always an integer and does not need to be checked.
Usman Saleem
2021-1-2
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