Reorder Matrix Rows from the row with the most nonzero elements to the row with the least nonzero elements
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I have a matrix with rows of values. I want to order the rows of the matrix so that the matrix with the most nonzero elements is the first row and the next most nonzero elements is the second row, and so on until the end. If two or rows are the same length it doesnt matter which one comes first. Here is the matrix, thanks in advance.
A = [0 1 2 4 7 12 17 22 27 33 42
0 0 1 3 6 11 16 21 26 34 43
0 1 2 4 7 12 17 22 28 35 44
0 0 1 2 8 13 18 23 29 36 45
0 0 1 3 9 14 19 24 30 37 46
0 1 2 5 10 15 20 25 31 38 47
0 1 3 6 11 16 21 26 32 39 48
1 2 4 7 12 17 22 27 33 40 49
0 1 2 5 10 15 20 25 31 41 50];
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Stephen23
2021-1-5
Curious. Apparently not homework, but the same question was asked by multiple OPs at the same time:
Backup just in case:
回答(2 个)
Cris LaPierre
2021-1-5
I'm not aware of anyway to do this without having to write some code, which is probably the exact reason you were given the assignment. Look into logical indexing and sortrows.
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Stephen23
2021-1-5
A = [...
0 1 2 4 7 12 17 22 27 33 42
0 0 1 3 6 11 16 21 26 34 43
0 1 2 4 7 12 17 22 28 35 44
0 0 1 2 8 13 18 23 29 36 45
0 0 1 3 9 14 19 24 30 37 46
0 1 2 5 10 15 20 25 31 38 47
0 1 3 6 11 16 21 26 32 39 48
1 2 4 7 12 17 22 27 33 40 49
0 1 2 5 10 15 20 25 31 41 50];
[~,X] = sort(sum(A==0,2));
B = A(X,:)
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