Defining values into zeros matrix
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How can i define all s4 values in a FIRSTSPACE?
LOWERLIMIT = 1 ;
UPPERLIMIT = 360 ;
FIRSTSPACE=zeros(LOWERLIMIT,UPPERLIMIT);
for q=(0:1:360)
s4=[(0.096.*cos(q))-(0.168.*sin(q))]
end
采纳的回答
Sriram Tadavarty
2021-1-5
Hi,
You can directly execute
q= 0:1:360;
s4=[(0.096.*cos(q))-(0.168.*sin(q))]
Regards,
Sriram
3 个评论
Sriram Tadavarty
2021-1-5
s4 variable is of length 361, since the for loop starts from 0.
To only get the values from 1 to 360, use
FIRSTSPACE = s4(1:360); % Or FIRSTSPACE = s4(LOWERLIMIT:UPPERLIMIT);
Hope this helps.
Ilhami Alp Silahtaroglu
2021-1-5
Sriram Tadavarty
2021-1-5
Using for loop is not apt here.
But, just in-case you only need it as such. Here is it:
LOWERLIMIT = 1 ;
UPPERLIMIT = 361 ;
FIRSTSPACE=zeros(LOWERLIMIT,UPPERLIMIT);
for q=(0:1:360)
FIRSTSPACE(q+1) = [(0.096.*cos(q))-(0.168.*sin(q))];
end
Regards,
Sriram
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