integral square error calculation

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apoorv srivastava
评论： apoorv srivastava 2021-1-7
i want to calculate ise of a transfer function for which i have to claculate inverse laplace
this is my code...
num=[3 2]
den=[155.0388 33.5652 2]
R2=tf(num,den)
num1=[1 8 20 16 3 2]
den1=[1 18.3 102.4 209.5 155.9 33.6 2]
G6=tf(num1,den1)
E=G6-R2
et=ilaplace(E)
gives an error
please help me out in calculation of ise for E

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回答（1 个）

Walter Roberson
Walter Roberson 2021-1-7
编辑：Walter Roberson 2021-1-7
  3 个评论
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Walter Roberson
Walter Roberson 2021-1-7
FT_time_domain is going to be symbolic -- in particular a symbolic sum of 8 roots of a polynomial is used multiple times in the expression.
collect() on it is not going to have any useful effect as there are no exp(-t) terms -- the terms are exp(something*t) and collect() is not smart enough to collect those. But doing the collect() does not hurt.
Either way the result of the collect() is going to be symbolic in the variable t .
You cannot trapz() a symbolic expression.
You could, however,
endtime = 1; %as appropriate
ise = trapz(0.1, subs(FT_time_domain, t, 0:0.1:endtime).^2)
apoorv srivastava
apoorv srivastava 2021-1-7
is there any other simplified way to solve this problem.
i just want to find ise of
Error = 152 s^7 + 1217 s^6 + 3027 s^5 + 2335 s^4 + 155.5 s^3 + 30.17 s^2 - 0.0696 s
--------------------------------------------------------------------------------------------------------------------------------------------
155 s^8 + 2871 s^7 + 1.649e04 s^6 + 3.595e04 s^5 + 3.141e04 s^4 + 1.086e04 s^3 + 1750 s^2 +
134.3 s + 4
please help me out..

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