FFT of a function

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ong 2013-4-11

I would like to do a FFT of x, x=cos(2*pi*f*t)

How can i replace X(W) = FFT(X) --> X(W/a) = ?

Thanks.

themaze 2013-4-11

Here is a nice way to accomplish that

I am assuming that w = 2*pi*f. Also you need to define your t

Xw = @(w, t) fft(cos(w*t));

to call the function, just use

Xw(w, t) or Xw(W/a, t)

ong 2013-4-11

Hi, thanks for the respond. What does the @ component do?

MATLAB Mathematics Fourier Analysis and Filtering

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