Column multiplication of two 2D matrices.

4 次查看（过去 30 天）
Nikan Fakhari
Nikan Fakhari 2021-1-13
编辑： Bruno Luong 2021-1-14
Hi there,
I have two quite large matrices with the following sizes:
A = rand(94037,2240) B=rand(2240,2240)
I would like to mutiply each column of A by the transpose of each column of B (bascially two vector multiplication). Therefore each mutiplcation gives me a 2D matrix wih size (94037,2240) and I would like to store the result of each multiplication in a 3d MATRIX.
The thing is I can do this with for-loop as show below but its very slow and in the middle of operation matlab exist, because its quite heavy.
S = zeros(94037,2240,2240);
for i=1:1:2240
S(:,:,i) =A(:,i)*(B(:,i))';
end
Is there anyway I can do this without using for loop to speed up the process ?
Thanks for the help.
Best,
Nikan
  2 个评论
Matt J
Matt J 2021-1-13
Outer products are often both an inefficient and an avoidable step in many computations. What do you plan to do with S once you've computed it?
Nikan Fakhari
Nikan Fakhari 2021-1-13
I am planning to take sum along the third dimension

请先登录，再进行评论。

请先登录，再回答此问题。

回答（2 个）

Matt J
Matt J 2021-1-13
编辑：Matt J 2021-1-13
I am planning to take sum along the third dimension
That would simply give you A*B.'
Matt J
Matt J 2021-1-13
编辑：Matt J 2021-1-14
I doubt you will be able to do the computation with the matrix sizes you've indicated. The result will consume 3.5 TB of RAM in double floating point. However, if you can scale down the matrix sizes, then a loop-free solution is as follows,
[ma,na]=size(A);
[mb,nb]=size(B);
S=reshape(A,ma,1,na).*reshape(B,1,mb,nb);
  2 个评论
Bruno Luong
Bruno Luong 2021-1-14
编辑：Bruno Luong 2021-1-14
I guess there is a typo. The right command has no brakets
S = reshape(A,ma,1,na) .* reshape(B,1,mb,nb);

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Programming 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by