Different results for the same equation
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lambda(1) is displayed the same as lambda(3) but its value is not identical to the value of lambda(3).
A = [-10 10 -15; 10 5 -30; -5 -10 0];
lambda = eig(A)
lambda(1) == lambda(3) % false
lambda(1)-lambda(3) % very small but not 0
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Diana
2021-1-14
A = [-10 10 -15; 10 5 -30; -5 -10 0];
lambda = eig(A)
lambda(1) + 15
lambda(3) + 15
The third lambda is an exact integer. When you calculate A-lambda(3)*eye(3) you get exact integers, and rref() is able to calculate exact integer outputs.
When you use format short (which is the default) and all of the outputs to be displayed are exact integers, then no decimal points are shown. When any of the outputs are not exact integers, then decimal points are shown in all of the outputs.
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2021-1-14
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