Summation of values > 1 in a cell array
显示 更早的评论
Suppose I've a cell array;
cnt{1}=[3;1;3;2;1;2]
I would like to sum up the values which are > 1 ie the answer should return 10 (3+3+2+2)
I've tried using 'find' but the answer only returns the indices of the values > 1 and not the values.
ind=(find(cnt{1}>1))
How can I go about this? Please give me some hint.
采纳的回答
Ilham Hardy
2013-4-12
sumVal = sum(cnt{1})-length(find(cnt{1}==1))
3 个评论
Even if you wanted to do it this way, FIND is unnecessary
sumVal = sum(cnt{1})-sum(cnt{1}==1),
or
sumVal = sum(cnt{1})-sum(cnt{1}(cnt{1}<=1)),
Ilham Hardy
2013-4-12
Yes, i agree. This way will be faster.
However i don't fully get the differences between example#1 and example#2. Care to explain?
Matt J
2013-4-12
The 2nd method would be needed if the threshold were something other than 1.
更多回答（1 个）
ind=(cnt{1}>1);
sum(cnt{1}(ind)),
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