Why is EACH function evaluation inside a parfor loop much faster then ONE evaluation outside the loop?

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Sargondjani 2021-1-16

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https://ww2.mathworks.cn/matlabcentral/answers/718740-why-is-each-function-evaluation-inside-a-parfor-loop-much-faster-then-one-evaluation-outside-the-loo

Basically I calculate a finite difference Jacobian of a function, as shown below.

The function evaluation labelled SINGLE RUN takes about 60 seconds, and the ones labelled PARALLEL RUN take about 20 seconds.

Any clue why this might be?

Note: the "dx=0.1" does not have any influence on the speed of myfun.

myfun = @(x).... %the function of interest, which has a tic/toc inside it
[Jac] = jacob_paral(myfun,x0)
function [Jac] = jacob_paral(myfun,x0)
%SINGLE RUN:
y0  = feval(myfun,x0);
nn = length(x0);
Jac = NaN(length(y0),nn);
parfor ix = 1:nn
    dx = zeros(1,nn)
    dx(ix) = 0.01;
    x = x0+dx;
    %PARALLEL RUN:
    y = feval(myfun,x);
    Jac(:,ix) = (y-y0)./dx(ix)
end

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Why is EACH function evaluation inside a parfor loop much faster then ONE evaluation outside the loop?

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