How to find indices of non duplicate rows in a matrix?

Question

Luca M 2021-1-20

编辑： Luca M 2021-1-21

采纳的回答： dpb

I need to find the indices of non duplicate rows in a matrix and I am not sure if there is a way to do it with:

unique()

if for example in the vector case I have:

A = [1 1 2 2 3 4 5 6 6]

I'd like to produce (as these 3 elements are unique in A):

B = [3 4 5]

by using:

A(unique_indices)

after somehow building:

unique_indices = [5 6 7]

in this case. The unique function will return a single copy of each element. Is there a quick way to do it? Thanks for tips.

Answer 1

dpb 2021-1-20

>> A = [1 1 2 2 3 4 5 6 6];
>> [n,b]=histc(A,unique(A));
>> A(ismember(b,find(n==1)))
ans =
          3.00          4.00          5.00
>> 

Luca M 2021-1-21

Thanks.