How i can graph in 3 dimension, dependent of the temperature?

1 次查看(过去 30 天)
Good day for everyone, i have a simple question. I have matlab R2019a. My question is..
How i can graph this equation:
T = - 3 (x^2+y^2+z^2)^(1/2) + 300
is a room that is dependent of temperature in all directions
I tried this, but doesn't appear the graph
syms x y z
T0 = 300
f = -3*sqrt((x^2+y^2+z^2))+ T0;
fimplicit3(f, [0 0 0])
Thank you so much for your valious time.

回答(0 个)

类别

Help CenterFile Exchange 中查找有关 2-D and 3-D Plots 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by