How to input signal to skip numbers and generate data?

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Leon Low 2021-1-27

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https://ww2.mathworks.cn/matlabcentral/answers/728518-how-to-input-signal-to-skip-numbers-and-generate-data

评论： Mara 2021-1-29

I have a set of random 0s and 1s matrix A = [0 0 0 0 0 1 1 1 0 0 0 0 1 0 1 1 0 0 1 1 1 1 1 0 0 0 0]. I want to create a matrix B that has the same size as A that if i input an interval of say 'n', it skips n numbers, and if it lands on 1, it records 1 but if it lands on 0 it records 0. however, if it doesnt land on 1 for a long time and finally lands on a 1, it records a 1 even though it has skipped more than n numbers. How do I create this matrix B?

For example, n = 2, then matrix B = [0 0 0 0 0 1 0 0 0 0 0 0 1 0 0 1 0 0 1 0 0 1 0 0 0 0 0]

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Answer 1

Mara 2021-1-27

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https://ww2.mathworks.cn/matlabcentral/answers/728518-how-to-input-signal-to-skip-numbers-and-generate-data#answer_607573

在 MATLAB Online 中打开

A       = [0 0 0 0 0 1 1 1 0 0 0 0 1 0 1 1 0 0 1 1 1 1 1 0 0 0 0];
n       = 2;
B       = zeros (1,length(A));
count   = 0;
for i = 1:length(A)
    count = count + 1;
    if A(i) == 1 && count > n
        B(i) = 1;
        count = 0;
    end  
end

Does this help you?

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Mara 2021-1-27

编辑：Mara 2021-1-27

在 MATLAB Online 中打开

Hey Leon, glad I could help. If you know the position you want to start with, I think the easiest way might be to include another if statement. If i is taller than or equal to the start position 7, it starts skipping and before that it will just copy the elements of A one by one.

A       = [0 0 0 0 0 1 1 1 0 0 0 0 1 0 1 1 0 0 1 1 1 1 1 0 0 0 0];
n       = 2;
B       = zeros (1,length(A));
count   = n;    % the starting value of count needs to be changed if
                %  you want to be able to start skipping with a 1 right away
start   = 7;
for i = 1:length(A)
    if i >= start
        count = count + 1;
        if A(i) == 1 && count > n
            B(i)    = 1;
            count   = 0;
        end 
    else
        B(i) = A(i)
    end
end

or this way, make B a copy of A right at the beginning and then start looping from the starting position.

A       = [0 0 0 0 0 1 1 1 0 0 0 0 1 0 1 1 0 0 1 1 1 1 1 0 0 0 0];
n       = 2;
B       = A;
count   = n; % if you want to be able to start skipping with a 1 right away
start = 7;
for i = start:length(A)
        count = count + 1;
        if A(i) == 1 && count > n
            B(i)    = 1;
            count   = 0;
        else 
            B(i) = 0;
        end 
end