Deleting empty rows in a 3D Cell Array in MatLab
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I have a large 3D CELL ARRAY (x1) which I have to delete the empty rows. How can I do this?
Example of my cell array (some pieces of the variable):
val(:,:,1) =
[20] [] [] [] [] []
[ 0] [] [] [] [] []
[ 0] [] [] [] [] []
[] [] [] [] [] []
(...)
val(:,:,42) =
[ 34225] [ 215] [ 0] [ 0] [ 0] [ 0]
[ 85200] [ 545] [ 0] [ 0] [ 0] [ 0]
[ 65074] [ 190] [ 1000] [ 0] [ 0] [ 0]
[ 81570] [ 1385] [ 2475] [ 0] [ 0] [ 0]
[ 67236] [ 530] [ 365] [ 0] [ 0] [ 0]
[ 61338] [ 0] [ 100] [ 0] [ 0] [ 0]
[] [] [] [] [] []
[] [] [] [] [] []
[] [] [] [] [] []
In this case, I want to exclude the 4th row of `(:,:,1)`, the three last rows from `(:,:,42)` and all the others from these variable.
I've tried
x1(all(all(cellfun((@isempty,x1),2),:,:) = [];
But it gave me this following error:
Error: Expression or statement is incorrect--possibly unbalanced (, {, or [.
PS: I cannot use `"=="` because its a cell array.
Thanks in advance
2 个评论
You cannot erase the 4th row of val(:,:,1) without erasing as well the 4th row for all valid 3rd indices. In your example, doing this would erase val(4,:,42) as well.. is it what you want to do?
Also, your example should show that val(:,:,1) and val(:,:,42) have the same size (for val to be a 3D cell array). Are you sure that you don't have a cell array of 2D cell arrays? (you index val as a 3D cell array though)
Luiz
2013-4-23
采纳的回答
Cedric
2013-4-23
If you want to be able to remove rows from single "pages", you should use a cell array of cell arrays, e.g.
A = cell(3, 1) ;
A{1} = {2, 3, 4; [], [], []; [], 5, []} ;
A{2} = {9} ;
A{3} = {2, 3, 4, 5, 6; [], 9, [], [], []; ...
[], [], [], [], []; [], [], [], [], []} ;
for k = 1 : length(A)
id = all(cellfun(@isempty, A{k}), 2) ;
A{k}(id,:) = [] ;
end
After execution, we get:
>> A{1}
ans =
[2] [3] [4]
[] [5] []
>> A{2}
ans =
[9]
>> A{3}
ans =
[2] [3] [4] [5] [6]
[] [9] [] [] []
and you can see that the content of cells of A doesn't need to match in size.
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