How to use "trapz" on a double integral?

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Lia
Lia 2013-4-23
评论: Torsten 2016-1-18
I have a double integral where f = integral (x.^4 - 3*x*y +6*y.^2)dxdy with the outer limits -2 to 2 and the inner limits are 0 to 3. I am supposed to evaluate this integral using Matlab's built in function "trapz" and set the segment width in the x and y- directions at h = 0.1.
Here's what I have so far:
% integration limits
a = -2; b = 3; n = 2;
% given function
f = @(w,y) ((w.^4) - (3*w*y) + (6*(y^2)))
% implement composite trapezoidal rule
trapz(f,a,b)
I know that I am pretty far off from getting the answer, so I apologize and hopefully don't look too dumb.
  3 个评论
Torsten
Torsten 2016-1-18
Take a look at the example "Multiple Numerical Integrations" under
Best wishes
Torsten.

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回答(2 个)

John BG
John BG 2016-1-17
try
x1=-2;dx=.1;x2=2;
y1=0;dy=.1;y2=3
[X,Y]=meshgrid(x1:dx:x2,y1:dy:y2)
Z=X.^4-3*X.*Y+6*Y.^2
x=x1:dx:x2;y=y1:dy:y2
I=trapz(y,trapz(x,Z,2))
you can visualize the curve with
surf(Z)
mind the negative values
find(Z<0)
meaning the curve is not positive for all values in the patch to run the double integral through. If attempting to measure power, square any function. Hope it helps
John

Sean de Wolski
Sean de Wolski 2013-4-24
Instead of using trapz, try integral2().
doc integral2
If you are on an olde release that does not have integral2, try dblquad.
doc dblquad

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