Compare Row & only keep the highest value

1 次查看（过去 30 天）
Aninda Maji
Aninda Maji 2021-2-3
编辑： Aninda Maji 2021-2-3
I have a matrix like this:
A:
100 0.35
200 0.37
300 0.42
400 0.40
500 0.39
600 0.46
I want the output like this:
B:
100 0.35
200 0.37
300 0.42
400 0.42
500 0.42
600 0.46
I.e. what I need is in the second column compare each row against previouos row. In case current row is higher than the previous row then keep it but if the previous row is higher then copy the prvious row in the current row.
I am aware that I can do it via a for loop. But is there any way to do it a more clean way through matrix operation?
Many thanks in advance for your help.

请先登录，再回答此问题。

采纳的回答

Jan
Jan 2021-2-3
编辑：Jan 2021-2-3
A = [100, 0.35; ...
200, 0.37; ...
300, 0.42; ...
400, 0.40; ...
500, 0.39; ...
600, 0.46];
B = [A(:, 1), cummax(A(:, 2))]
Or in your case:
B = cummax(A, 1) % Along 1st dimension
  1 个评论
Aninda Maji
Aninda Maji 2021-2-3
编辑：Aninda Maji 2021-2-3
Super this works as expected,
Now I have the matrix like this:
A =
[100 0.35;
200 0.38;
300 0.40;
400 0.40;
500 0.42;
600 0.42;
700 0.42;
800 0.48];
B =
[100 0.35;
200 0.38;
300 0.40;
400 0.41;
500 0.42;
600 0.44;
700 0.46;
800 0.48];
So what this B does is it check the data points to calculate where we have same values there it evenly distributes between the 2 points. so for 400 data becomes to 0.41 (0.40+(0.42 - .40/2)) and for 600, 700 data becomes 0.44 and 0.46 respectively (0.42+((.48-.42)/3)*1) & (0.42+((.48-.42)/3)*2).
Is there any simple of way of doing it?

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by