Please help with the trig integral

2013 4 25
1 个回答
9 次查看（30 天）

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I'm trying to take the integral of the following function.
arctan[sin(phi)/sqrt{(sin(x)^2-sin(phi)^2}]*sinx*dx
The interval is (degree10, degree15)
phi=9.4 degree
Here is what I have
fi=9.4*pi/180;
theta1=10*pi/180;
theta2=15*pi/180;
fun1=@(x)sqrt((sin(x)).^2-(sin(fi)).^2);
fun2=@(x)atan(sin(fi)./fun1).*sin(x);
q=integral(fun2,theta1,theta2);
Thank you very much!

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回答（1 个）

Mike Hosea
Mike Hosea 2013-4-25

0 个投票

On the line defining fun2, change "fun1" to "fun1(x)".

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Jake
Jake
2013-4-25

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