Generating non-repeating numbers by using a for-loop and break statement

14 次查看（过去 30 天）
Vanessa Huijgevoort
回答： dpb 2021-2-4
Dear all,
I need to make a function that generates a vector x of n random but unique elements that are smaller or equal to m. If a number is repeated, the function should return an empty vector. If not, the function should just return x. I tried using a for-loop and break statement, but they aren't really working properly. This is my code:
function random=r(m,n)
x=randi(m,1,n);
for i=1:m
if sum(x==i)>1
break
disp('[]');
else
disp(x);
end
end
end
Could someone tell me what I'm doing wrong?
Thanks in advance!
Vanessa
  3 个评论
显示 1更早的评论
dpb
dpb 2021-2-4
Above answers why the function doesn't display the empty return case; you could remove the need for a loop entirely
function random=r(m,n)
x=randi(m,1,n);
if numel(unique(x)<m)
disp('[]');
else
disp(x);
end
end

请先登录，再进行评论。

请先登录，再回答此问题。

回答（1 个）

dpb
dpb 2021-2-4
The function doesn't return anything, though...either your original nor mine. I didn't catch that before. If the idea is to return the generated vector if it is unique or an empty vector [] if there is a duplication, then need
function x=r(m,n)
x=randi(m,1,n);
if numel(unique(x)<m)
x=[];
end
end
Above I've also presumed it really is intended to just echo the result to the command line but to return the requested data instead.

类别

在 Help Center 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by