Problem finding max value of column of an Matrix

2 次查看(过去 30 天)
Dear Experts,
I have some loop problem in matlab, I can't find where is the exact problem in my loop , Could please help me in that :)
A = [ 0 1 2 3 4 25 6 7 8 9 ; 9 5 1 20 3 6 4 7 8 5]'
for i=1:size(A,1) for n=1:size(A,2) if A(i,n) == max(A(:,n)) A(i,n)=1 else A(i,n)=0 end end end
the Correct result I expect from the program like this :
0 0
0 0
0 0
0 1
0 0
1 0
0 0
0 0
0 0
0 0
But I getting the error result like
0 0
0 0
0 0
0 1
0 0
1 0
0 0
0 0
0 1
1 1
Many thanks
Good weekend
With Regards
Sayanta

采纳的回答

Laura Proctor
Laura Proctor 2011-5-13
A = [ 0 1 2 3 4 25 6 7 8 9 ; 9 5 1 20 3 6 4 7 8 5]'
c1 = A(:,1) == max(A(:,1));
c2 = A(:,2) == max(A(:,2));
A = [c1 c2];
You'll end up with a logical array as a result, but it will give the results you want. If it needs to be an array of type double, just cast it to double:
double(A)
If you would like to not create variables c1 and c2, then you can just replace c1 with A(:,1) and c2 with A(:,2) which will result in A as type double.
The problem with your initial code is that you're overwriting values in A in each loop.

更多回答(1 个)

Andy
Andy 2011-5-13
The problem you're having is that you recalculate the max of each column on each iteration of the loop. You could move that calculation out of the loop, or not use a loop at all:
A = [ 0 1 2 3 4 25 6 7 8 9 ;
9 5 1 20 3 6 4 7 8 5]';
[dummy,mA] = max(A,[],1); % max of each column
B = zeros(size(A));
B(sub2ind(size(A),mA,[1 2]))=1; % enter 1s for each max

类别

Help CenterFile Exchange 中查找有关 Loops and Conditional Statements 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by