Calculates the mean if the difference of two or more number is 1

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edward kabanyas 2021-2-7

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https://ww2.mathworks.cn/matlabcentral/answers/738927-calculates-the-mean-if-the-difference-of-two-or-more-number-is-1

评论： edward kabanyas 2021-2-9

采纳的回答： Matt Gaidica

Hi all;

I want to calculate mean of numbers if their difference with its neighbor is 1 . For example, if I have a matrix:

A = [9 10 12 14 15 16 18 19 22 23 25];

For each number whose difference with the neighbors is one, their mean is calculated. So, the intended result (called as matrix B):

B [9.5 12 15 18.5 22.5 25];

I try to use:

diff(A), so we get

1 2 2 1 1 2 1 3 1 2

But, how to use this diff(A) to do an operation , so that we get the resul: B [9.5 12 15 18.5 22.5 25];

Thank you for help.

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采纳的回答

Matt Gaidica 2021-2-8

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/738927-calculates-the-mean-if-the-difference-of-two-or-more-number-is-1#answer_617367

编辑：Matt Gaidica 2021-2-8

在 MATLAB Online 中打开

A = [9 10 12 14 15 16 18 19 22 23 25];
idx = find(diff(A)==1);
B = mean([A(idx);A(idx+1)])

I think you have a typo above, 25 would not be in the final array:

B =
    9.5000   14.5000   15.5000   18.5000   22.5000
    

Could also:

mv = movmean(A,2);
idx = find(diff(A)==1);
B = mv(idx+1)

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Matt Gaidica 2021-2-8

在 MATLAB Online 中打开

Not my proudest code snippet, but at least you can step through it and see what's going on:

A = [9 10 12 14 15 16 18 19 22 23 25];
B = [];
arr = [];
ii = 1;
while ii <= numel(A)
    arr(1) = A(ii);
    while ii~= numel(A) && A(ii+1) == A(ii)+1
        arr = [arr A(ii+1)];
        ii = ii + 1;
        if ii > numel(A) - 1
            break;
        end
    end
    B = [B mean(arr)];
    ii = ii + 1;
    arr = [];
end
B