Calculates the mean if the difference of two or more number is 1

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edward kabanyas
edward kabanyas 2021-2-7
评论： edward kabanyas 2021-2-9
Hi all;
I want to calculate mean of numbers if their difference with its neighbor is 1 . For example, if I have a matrix:
A = [9 10 12 14 15 16 18 19 22 23 25];
For each number whose difference with the neighbors is one, their mean is calculated. So, the intended result (called as matrix B):
B [9.5 12 15 18.5 22.5 25];
I try to use:
diff(A), so we get
1 2 2 1 1 2 1 3 1 2
But, how to use this diff(A) to do an operation , so that we get the resul: B [9.5 12 15 18.5 22.5 25];
Thank you for help.

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Matt Gaidica
Matt Gaidica 2021-2-8
编辑：Matt Gaidica 2021-2-8
A = [9 10 12 14 15 16 18 19 22 23 25];
idx = find(diff(A)==1);
B = mean([A(idx);A(idx+1)])
I think you have a typo above, 25 would not be in the final array:
B =
9.5000 14.5000 15.5000 18.5000 22.5000
Could also:
mv = movmean(A,2);
idx = find(diff(A)==1);
B = mv(idx+1)
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Matt Gaidica
Matt Gaidica 2021-2-8
Not my proudest code snippet, but at least you can step through it and see what's going on:
A = [9 10 12 14 15 16 18 19 22 23 25];
B = [];
arr = [];
ii = 1;
while ii <= numel(A)
arr(1) = A(ii);
while ii~= numel(A) && A(ii+1) == A(ii)+1
arr = [arr A(ii+1)];
ii = ii + 1;
if ii > numel(A) - 1
break;
end
end
B = [B mean(arr)];
ii = ii + 1;
arr = [];
end
B

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