datatypes

'e1' is a string, which is an array of character, and applying double to the array of character returns the numeric values of each of the characters: that happens to be 101 for 'e' and 49 for '2'. For more information on this, please see Command vs Function syntax

In MATLAB, one does not declare variables as being of a particular type: one just assigns values and the variable assumes the type of the values if the variable appears by itself (without any kind of indexing) in an assignment syntax.

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sheen 2011-5-15

% high weights of current project

j = [1.15, 1.08, 1.15, 1.11, 1.06, 1.15, 1.07, 1.07, 0.91, 0.86, 0.90, 0.95, 0.91, 0.91, 1.04];

% nominal weights of previous project

l = [1.00, 1.00 , 1.00 ,1.00, 1.00, 1.00, 1.00, 1.00, 1.00, 1.00, 1.00, 1.00, 1.00, 1.00, 1.00];

m = [1.05, 1.12, 1.2];

z = [46, 16, 4, 6.9, 22, 30, 18, 20, 37, 24, 3, 3.9, 3.7, 1.9, 75, 90, 38, 48, 9.4, 13, 2.14, 1.98, 50, 40, 22, 13, 12, 34, 15, 6.2, 2.5, 5.3, 19.5, 28, 30, 32, 57, 23, 91, 24, 10, 8.2, 5.3, 4.4, 6.3, 27, 15, 25, 21, 6.7, 28, 9.1,10];

t = 17;

%size

y = z(1:3);

%for k = 0 : j % its mean that I will take 12 values of matrix j in loop ok k and store these values in x, so I could use x in further calculations and whole 12 values will be used one by one by loop vie variable x.same is the case with other for loops..

x = j(k);

end % end is omitted by you? Is there no need to use it?

for n = 0 : 2

a = m(n)

end

% sum of importance weights of current project

s = a + x + y;

b = s / t;

for c = 0 : l

h = l(c)

end

% sum of importance weights of previous project

e = a + d + y;

f = e / t;

p = 24.5 ;

g = f * p;

% individual distance

d = b - g;

disp(d)

plz check it.

sheen 2011-5-15

% high weights of current project

j = [1.15, 1.08, 1.15, 1.11, 1.06, 1.15, 1.07, 1.07, 0.91, 0.86, 0.90, 0.95, 0.91, 0.91, 1.04];

% nominal weights of previous project

l = [1.00, 1.00 , 1.00 ,1.00, 1.00, 1.00, 1.00, 1.00, 1.00, 1.00, 1.00, 1.00, 1.00, 1.00, 1.00];

m = [1.05, 1.12, 1.2];

t = 17;

%size

y = z(1:3);

x = j(k);

end % end is omitted by you? Is there no need to use it?

for n = 0 : 2

a = m(n)

end

% sum of importance weights of current project

s = a + x + y;

b = s / t;

for c = 0 : l

h = l(c)

end

% sum of importance weights of previous project

e = a + d + y;

f = e / t;

p = 24.5 ;

g = f * p;

% individual distance

d = b - g;

disp(d)

plz check it.

sheen 2011-5-21

d (P1, P2) =

M j j-1

∑ Q( (∑ (u )/T) - Q ((∑ (u )/T) * d v (P1,P2)

(j=1) (k=1) k (k=1) k j

i have written code for this eq.

j=1 is subscrtipt of first summation.and M is superscript of first summation and so on.i hope u will understand my problem now.for u with k as subscrit , i have taken size, modes and cost drivers.please tell me how to correct my code?

sheen 2011-5-21

j is superscript of second summation , j-1 is superscript of third summation.k=1 is subscript of second summation,k is of u, k=1 is of third summation and j issubscript of v.

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