Using the answer of inputdlg into a Matlab Expression

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Alessandro 2013-4-30

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https://ww2.mathworks.cn/matlabcentral/answers/74081-using-the-answer-of-inputdlg-into-a-matlab-expression

编辑： MoeIsKing 2018-11-14

Hello everybody,

I am trying to write some piece of code which asks for the name of a previously defined variable and uses the answer in some calculations. Everything works fine when I use 'input' to ask for that name. But I want to use the 'inputdlg' command. The problem is that 'inputdlg' returns user input in a cell array. I tried converting the cell with 'str2double' but that only works for numbers (won't work when trying to convert the name of the variable!). This is the piece of code:

Source = inputdlg('Name given to the vector containing the sample: ');
Fs = inputdlg('Sampling Frequency: '); % Sampling frequency
Fs = str2double(Fs);
Source = str2double(Source(1,1));
T = 1/Fs; % Sample time
L = length(Source); % Length of signal
t = (0:L-1)*T; % Time vector
NFFT = 2^nextpow2(L); % Next power of 2 from length of y
Y=fft(Source,NFFT)/L;

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Azzi Abdelmalek 2013-4-30

What is the error message?

Alessandro 2013-4-30

编辑：Alessandro 2013-4-30

For example, if the vector I want to select is 'A', 'Source' vector will be composed of a single entry 'A' instead of being equal to the original vector. Note this does not happen when using 'input' command instead of 'inputdlg'.

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Answer 1

Azzi Abdelmalek 2013-4-30

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https://ww2.mathworks.cn/matlabcentral/answers/74081-using-the-answer-of-inputdlg-into-a-matlab-expression#answer_83931

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Use

Source = char(Source)

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Alessandro 2013-4-30

That doesn't work as well, because the so-created Source is a char-type array containing 1 entry instead of being set equal to the vector specified in the inputdlg box.

Alessandro 2013-4-30