I want to know the value of x for each value of V

Question

Pablo Zarco 2021-2-10

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/741802-i-want-to-know-the-value-of-x-for-each-value-of-v

评论： Cris LaPierre 2021-2-10

V=[2,4,5,6,7]
for i=1:numel(V)
x(i)=(2+4*7+8-9*6+x(i))/(3+4*6*V(i)+3*x(i))
end

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the cyclist 2021-2-10

Can you please use more than one sentence to describe what you are trying to do? You have not given enough information for us to help you.

Pablo Zarco 2021-2-10

Is an equation with one variable. The thing is that I would like to know if there is a way to solve this without clearing the x

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Answer 1

Cris LaPierre 2021-2-10

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https://ww2.mathworks.cn/matlabcentral/answers/741802-i-want-to-know-the-value-of-x-for-each-value-of-v#answer_620322

编辑：Cris LaPierre 2021-2-10

You are using x to calculate x. This is causing an error since x doesn't exist yet.

What is the equation you are trying to implement in MATLAB?

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Pablo Zarco 2021-2-10

That is the equation. Is an equation with only one variable. Is there any way to solve this without operating by clearing the x?

Cris LaPierre 2021-2-10

在 MATLAB Online 中打开

V=[2,4,5,6,7];

fp=fplot(@(x)(2+4*7+8-9*6+x)./(3+4*6*V+3*x))

fp =

5×1 FunctionLine array: FunctionLine FunctionLine FunctionLine FunctionLine FunctionLine

legend("V="+num2str(V'))

Use the plot object to get the x and y data of each line. For example

x1 = fp(1).XData
x1 = 1×45
   -5.0000   -4.7914   -4.5455   -4.3075   -4.0909   -3.8679   -3.6364   -3.3856   -3.1818   -2.9285   -2.7273   -2.5080   -2.2727   -2.0542   -1.8182   -1.5647   -1.3636   -1.1199   -0.9091   -0.6699   -0.4545   -0.2294         0    0.2273    0.4545    0.6909    0.9091    1.1546    1.3636    1.5870
y1 = fp(1).YData
y1 = 1×45
   -0.5833   -0.5677   -0.5499   -0.5333   -0.5188   -0.5043   -0.4898   -0.4746   -0.4627   -0.4484   -0.4374   -0.4257   -0.4136   -0.4027   -0.3912   -0.3793   -0.3702   -0.3594   -0.3503   -0.3403   -0.3315   -0.3226   -0.3137   -0.3052   -0.2969   -0.2885   -0.2809   -0.2726   -0.2657   -0.2585